4261. 빠른 휴대전화 키패드

https://www.swexpertacademy.com/main/code/problem/problemDetail.do?contestProbId=AWLL7kaaAPsDFAUW&categoryId=AWLL7kaaAPsDFAUW&categoryType=CODE

SW Expert Academy

import java.io.BufferedReader;
import java.io.IOException;
import java.io.InputStreamReader;
import java.io.StringReader;
import java.util.HashMap;
import java.util.Map;
import java.util.StringTokenizer;

public class Solution {
	static BufferedReader br = new BufferedReader(new InputStreamReader(System.in));
	static StringBuilder sb;
	static StringTokenizer tokens;
	static int T;
	static int[][] map;
	static Map<Character, Integer> keymap = new HashMap<>();

	// 키의 매핑은 모든 상황에서 동일하게 지정됨
	private static void init() {
		for(char c='a'; c<='z'; c++) {
			if(c<='c') {
				keymap.put(c, 2);
			}else if(c<='f') {
				keymap.put(c, 3);
			}else if(c <='i') {
				keymap.put(c, 4);
			}else if(c<='l') {
				keymap.put(c, 5);
			}else if(c<='o') {
				keymap.put(c, 6);
			}else if(c<='s') {
				keymap.put(c, 7);
			}else if(c<='v') {
				keymap.put(c, 8);
			}else if(c<='z') {
				keymap.put(c, 9);
			}
		}
	}
	public static void main(String[] args) throws NumberFormatException, IOException {
		init();
		sb = new StringBuilder();

		br = new BufferedReader(new StringReader(src));
		T = Integer.parseInt(br.readLine());
		StringBuilder inputToNum = null;
		for (int t = 1; t <= T; t++) {
			int answer = 0;
			tokens = new StringTokenizer(br.readLine());
			String input = tokens.nextToken();
			tokens.nextToken();// 버림
			tokens = new StringTokenizer(br.readLine());
			String word = null;

			while(tokens.hasMoreTokens()) {
				word = tokens.nextToken();
				inputToNum = new StringBuilder();
				for(int i=0; i<word.length(); i++) {
					Character c = word.charAt(i);
					inputToNum.append(keymap.get(c));
				}
				if(input.equals(inputToNum.toString())) {
					answer++;
				}
			}
			sb.append(String.format("#%d %d\n", t, answer));
		}
		System.out.println(sb);
	}

	static String src = "3\r\n" +
			"6666 3\r\n" +
			"tomo mono dak\r\n" +
			"52 2\r\n" +
			"ja la\r\n" +
			"366 3\r\n" +
			"dom fon tom";
}